5/x-1=10/3x-4

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Solution for 5/x-1=10/3x-4 equation:



5/x-1=10/3x-4
We move all terms to the left:
5/x-1-(10/3x-4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x-4)!=0
x∈R
We get rid of parentheses
5/x-10/3x+4-1=0
We calculate fractions
15x/3x^2+(-10x)/3x^2+4-1=0
We add all the numbers together, and all the variables
15x/3x^2+(-10x)/3x^2+3=0
We multiply all the terms by the denominator
15x+(-10x)+3*3x^2=0
Wy multiply elements
9x^2+15x+(-10x)=0
We get rid of parentheses
9x^2+15x-10x=0
We add all the numbers together, and all the variables
9x^2+5x=0
a = 9; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·9·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*9}=\frac{-10}{18} =-5/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*9}=\frac{0}{18} =0 $

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