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5/x-2x/1=2x/x+3
We move all terms to the left:
5/x-2x/1-(2x/x+3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
5/x-2x/1-2x/x-3=0
We calculate fractions
(-2x^2)/x+(-2x+5)/x-3=0
We multiply all the terms by the denominator
(-2x^2)+(-2x+5)-3*x=0
We add all the numbers together, and all the variables
(-2x^2)-3x+(-2x+5)=0
We get rid of parentheses
-2x^2-3x-2x+5=0
We add all the numbers together, and all the variables
-2x^2-5x+5=0
a = -2; b = -5; c = +5;
Δ = b2-4ac
Δ = -52-4·(-2)·5
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{65}}{2*-2}=\frac{5-\sqrt{65}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{65}}{2*-2}=\frac{5+\sqrt{65}}{-4} $
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