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5/x-3/12=9/3x
We move all terms to the left:
5/x-3/12-(9/3x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5/x-(+9/3x)-3/12=0
We get rid of parentheses
5/x-9/3x-3/12=0
We calculate fractions
(-27x^2)/36x^2+180x/36x^2+(-108x)/36x^2=0
We multiply all the terms by the denominator
(-27x^2)+180x+(-108x)=0
We get rid of parentheses
-27x^2+180x-108x=0
We add all the numbers together, and all the variables
-27x^2+72x=0
a = -27; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-27)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-27}=\frac{-144}{-54} =2+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-27}=\frac{0}{-54} =0 $
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