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5/x-3=9-x
We move all terms to the left:
5/x-3-(9-x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
5/x-(-1x+9)-3=0
We get rid of parentheses
5/x+1x-9-3=0
We multiply all the terms by the denominator
1x*x-9*x-3*x+5=0
We add all the numbers together, and all the variables
-12x+1x*x+5=0
Wy multiply elements
x^2-12x+5=0
a = 1; b = -12; c = +5;
Δ = b2-4ac
Δ = -122-4·1·5
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{31}}{2*1}=\frac{12-2\sqrt{31}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{31}}{2*1}=\frac{12+2\sqrt{31}}{2} $
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