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5/x-4/5x=58
We move all terms to the left:
5/x-4/5x-(58)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
25x/5x^2+(-4x)/5x^2-58=0
We multiply all the terms by the denominator
25x+(-4x)-58*5x^2=0
Wy multiply elements
-290x^2+25x+(-4x)=0
We get rid of parentheses
-290x^2+25x-4x=0
We add all the numbers together, and all the variables
-290x^2+21x=0
a = -290; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-290)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-290}=\frac{-42}{-580} =21/290 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-290}=\frac{0}{-580} =0 $
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