5/x2

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Solution for 5/x2 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x > 2 // - 2

5/x-2 > 0

5*x^-1 > 2

5*x^-1 > 2 // : 5

x^-1 > 2/5

1/(x^1) > 2/5

x <> 0

1/(x^1) > 2/5 // * x^2

(x^2)/(x^1) > 2/5*x^2

x^1 > 2/5*x^2

x-2/5*x^2 > 0

x^1*(1-2/5*x) > 0

x < 0

-(abs(x))^1*(2/5*(abs(x))^1+1) > 0 // : -(abs(x))^1

2/5*(abs(x))^1+1 < 0

2/5*(abs(x))^1 < -1 // : 2/5

(abs(x))^1 < -1/2/5

(abs(x))^1 < -5/2 // ^ 1/1

abs(x) < (-5/2)^(1/1)

abs(x) < -5/2

x belongs to the empty set

x < 0

x > 0

x^1*(1-(2/5*x^1)) > 0 // : x^1

1-(2/5*x^1) > 0

1 > 2/5*x^1 // : 2/5

1/2/5 > x^1 // ^ 1/1

(1/2/5)^(1/1) > x

x in (0:5/2)

x > 0

x in (0:5/2)

x in (0:5/2)

(0:5/2)

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