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5/x=10/3x-1
We move all terms to the left:
5/x-(10/3x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x-1)!=0We get rid of parentheses
x∈R
5/x-10/3x+1=0
We calculate fractions
15x/3x^2+(-10x)/3x^2+1=0
We multiply all the terms by the denominator
15x+(-10x)+1*3x^2=0
Wy multiply elements
3x^2+15x+(-10x)=0
We get rid of parentheses
3x^2+15x-10x=0
We add all the numbers together, and all the variables
3x^2+5x=0
a = 3; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·3·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*3}=\frac{-10}{6} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*3}=\frac{0}{6} =0 $
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