5/x=4/2x+10

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Solution for 5/x=4/2x+10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

5/x = (4/2)*x+10 // - (4/2)*x+10

5/x-((4/2)*x)-10 = 0

5/x-2*x-10 = 0

5*x^-1-2*x^1-10*x^0 = 0

(5*x^0-2*x^2-10*x^1)/(x^1) = 0 // * x^2

x^1*(5*x^0-2*x^2-10*x^1) = 0

x^1

5-2*x^2-10*x = 0

5-2*x^2-10*x = 0

DELTA = (-10)^2-(-2*4*5)

DELTA = 140

DELTA > 0

x = (140^(1/2)+10)/(-2*2) or x = (10-140^(1/2))/(-2*2)

x = (2*35^(1/2)+10)/(-4) or x = (10-2*35^(1/2))/(-4)

x in { (2*35^(1/2)+10)/(-4), (10-2*35^(1/2))/(-4)} 

x in { (2*35^(1/2)+10)/(-4), (10-2*35^(1/2))/(-4) }

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