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5/x=5/3x+11
We move all terms to the left:
5/x-(5/3x+11)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+11)!=0We get rid of parentheses
x∈R
5/x-5/3x-11=0
We calculate fractions
15x/3x^2+(-5x)/3x^2-11=0
We multiply all the terms by the denominator
15x+(-5x)-11*3x^2=0
Wy multiply elements
-33x^2+15x+(-5x)=0
We get rid of parentheses
-33x^2+15x-5x=0
We add all the numbers together, and all the variables
-33x^2+10x=0
a = -33; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-33)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-33}=\frac{-20}{-66} =10/33 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-33}=\frac{0}{-66} =0 $
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