5/y+2=y/3

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Solution for 5/y+2=y/3 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+2 = y/3 // - y/3

5/y-(y/3)+2 = 0

5*y^-1-1/3*y^1+2*y^0 = 0

(2*y^1-1/3*y^2+5*y^0)/(y^1) = 0 // * y^2

y^1*(2*y^1-1/3*y^2+5*y^0) = 0

y^1

(-1/3)*y^2+2*y+5 = 0

(-1/3)*y^2+2*y+5 = 0

DELTA = 2^2-(4*5*(-1/3))

DELTA = 32/3

DELTA > 0

y = ((32/3)^(1/2)-2)/(2*(-1/3)) or y = (-(32/3)^(1/2)-2)/(2*(-1/3))

y = -3/2*((32/3)^(1/2)-2) or y = 3/2*((32/3)^(1/2)+2)

y in { -3/2*((32/3)^(1/2)-2), 3/2*((32/3)^(1/2)+2)}

y in { -3/2*((32/3)^(1/2)-2), 3/2*((32/3)^(1/2)+2) }

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