5/y+4+11/y2

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Solution for 5/y+4+11/y2 equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y+11/(y^2)+4 = 0

5*y^-1+11*y^-2+4 = 0

t_1 = y^-1

11*t_1^2+5*t_1^1+4 = 0

11*t_1^2+5*t_1+4 = 0

DELTA = 5^2-(4*4*11)

DELTA = -151

DELTA < 0

y belongs to the empty set

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