5/y=y-2/3

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Solution for 5/y=y-2/3 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

5/y = y-(2/3) // - y-(2/3)

5/y-y+2/3 = 0

5*y^-1-1*y^1+2/3*y^0 = 0

(2/3*y^1-1*y^2+5*y^0)/(y^1) = 0 // * y^2

y^1*(2/3*y^1-1*y^2+5*y^0) = 0

y^1

(2/3)*y-y^2+5 = 0

(2/3)*y-y^2+5 = 0

DELTA = (2/3)^2-(-1*4*5)

DELTA = 184/9

DELTA > 0

y = ((184/9)^(1/2)-(2/3))/(-1*2) or y = (-(2/3)-(184/9)^(1/2))/(-1*2)

y = ((184/9)^(1/2)-2/3)/(-2) or y = ((184/9)^(1/2)+2/3)/2

y in { ((184/9)^(1/2)-2/3)/(-2), ((184/9)^(1/2)+2/3)/2}

y in { ((184/9)^(1/2)-2/3)/(-2), ((184/9)^(1/2)+2/3)/2 }

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