50(20-x)+40x=300

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Solution for 50(20-x)+40x=300 equation: 



50(20-x)+40x=300

We move all terms to the left:

50(20-x)+40x-(300)=0

We add all the numbers together, and all the variables

50(-1x+20)+40x-300=0

We add all the numbers together, and all the variables

40x+50(-1x+20)-300=0

We multiply parentheses

40x-50x+1000-300=0

We add all the numbers together, and all the variables

-10x+700=0

We move all terms containing x to the left, all other terms to the right

-10x=-700

x=-700/-10

x=+70

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