50+(10x+11)=(21x-5)

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Solution for 50+(10x+11)=(21x-5) equation: 



50+(10x+11)=(21x-5)

We move all terms to the left:

50+(10x+11)-((21x-5))=0

We get rid of parentheses

10x-((21x-5))+11+50=0



We calculate terms in parentheses: -((21x-5)), so:

(21x-5)

We get rid of parentheses

21x-5

Back to the equation:

-(21x-5)



We add all the numbers together, and all the variables

10x-(21x-5)+61=0

We get rid of parentheses

10x-21x+5+61=0

We add all the numbers together, and all the variables

-11x+66=0

We move all terms containing x to the left, all other terms to the right

-11x=-66

x=-66/-11

x=+6

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