50+(3x-4)=2(3x-4)+27

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Solution for 50+(3x-4)=2(3x-4)+27 equation: 



50+(3x-4)=2(3x-4)+27

We move all terms to the left:

50+(3x-4)-(2(3x-4)+27)=0

We get rid of parentheses

3x-(2(3x-4)+27)-4+50=0



We calculate terms in parentheses: -(2(3x-4)+27), so:

2(3x-4)+27

We multiply parentheses

6x-8+27

We add all the numbers together, and all the variables

6x+19

Back to the equation:

-(6x+19)



We add all the numbers together, and all the variables

3x-(6x+19)+46=0

We get rid of parentheses

3x-6x-19+46=0

We add all the numbers together, and all the variables

-3x+27=0

We move all terms containing x to the left, all other terms to the right

-3x=-27

x=-27/-3

x=+9

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