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50+(x2)=(5x)+20
We move all terms to the left:
50+(x2)-((5x)+20)=0
We add all the numbers together, and all the variables
x^2-(5x+20)+50=0
We get rid of parentheses
x^2-5x-20+50=0
We add all the numbers together, and all the variables
x^2-5x+30=0
a = 1; b = -5; c = +30;
Δ = b2-4ac
Δ = -52-4·1·30
Δ = -95
Delta is less than zero, so there is no solution for the equation
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