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50+2x(x=10)
We move all terms to the left:
50+2x(x-(10))=0
We multiply parentheses
2x^2-20x+50=0
a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{4}=5$
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