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50+x(3*50+x)=1000
We move all terms to the left:
50+x(3*50+x)-(1000)=0
We add all the numbers together, and all the variables
x(x+150)+50-1000=0
We add all the numbers together, and all the variables
x(x+150)-950=0
We multiply parentheses
x^2+150x-950=0
a = 1; b = 150; c = -950;
Δ = b2-4ac
Δ = 1502-4·1·(-950)
Δ = 26300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26300}=\sqrt{100*263}=\sqrt{100}*\sqrt{263}=10\sqrt{263}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-10\sqrt{263}}{2*1}=\frac{-150-10\sqrt{263}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+10\sqrt{263}}{2*1}=\frac{-150+10\sqrt{263}}{2} $
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