50-(4x+5)=43-(7x+4)

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Solution for 50-(4x+5)=43-(7x+4) equation: 



50-(4x+5)=43-(7x+4)

We move all terms to the left:

50-(4x+5)-(43-(7x+4))=0

We get rid of parentheses

-4x-(43-(7x+4))-5+50=0



We calculate terms in parentheses: -(43-(7x+4)), so:

43-(7x+4)

determiningTheFunctionDomain
-(7x+4)+43

We get rid of parentheses

-7x-4+43

We add all the numbers together, and all the variables

-7x+39

Back to the equation:

-(-7x+39)



We add all the numbers together, and all the variables

-4x-(-7x+39)+45=0

We get rid of parentheses

-4x+7x-39+45=0

We add all the numbers together, and all the variables

3x+6=0

We move all terms containing x to the left, all other terms to the right

3x=-6

x=-6/3

x=-2

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