50/2t+4=2t+4/2

Solution for 50/2t+4=2t+4/2 equation:

50/2t+4=2t+4/2

We move all terms to the left:

50/2t+4-(2t+4/2)=0


Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R


We add all the numbers together, and all the variables

50/2t-(2t+2)+4=0

We get rid of parentheses

50/2t-2t-2+4=0

We multiply all the terms by the denominator


-2t*2t-2*2t+4*2t+50=0

Wy multiply elements

-4t^2-4t+8t+50=0

We add all the numbers together, and all the variables

-4t^2+4t+50=0

a = -4; b = 4; c = +50;
Δ = b2-4ac
Δ = 42-4·(-4)·50
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{51}}{2*-4}=\frac{-4-4\sqrt{51}}{-8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{51}}{2*-4}=\frac{-4+4\sqrt{51}}{-8}
$