500+30(n-3)=350+45(n-5)

Solution for 500+30(n-3)=350+45(n-5) equation:

500+30(n-3)=350+45(n-5)

We move all terms to the left:

500+30(n-3)-(350+45(n-5))=0

We multiply parentheses

30n-(350+45(n-5))-90+500=0


We calculate terms in parentheses: -(350+45(n-5)), so:

350+45(n-5)

determiningTheFunctionDomain
45(n-5)+350

We multiply parentheses

45n-225+350

We add all the numbers together, and all the variables

45n+125

Back to the equation:

-(45n+125)


We add all the numbers together, and all the variables

30n-(45n+125)+410=0

We get rid of parentheses

30n-45n-125+410=0

We add all the numbers together, and all the variables

-15n+285=0

We move all terms containing n to the left, all other terms to the right

-15n=-285

n=-285/-15

n=+19