500=20x2+00

Solution for 500=20x2+00 equation:

500=20x^2+00

We move all terms to the left:

500-(20x^2+00)=0

We get rid of parentheses

-20x^2-00+500=0

We add all the numbers together, and all the variables

-20x^2+500=0

a = -20; b = 0; c = +500;
Δ = b2-4ac
Δ = 02-4·(-20)·500
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*-20}=\frac{-200}{-40}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*-20}=\frac{200}{-40}
=-5
$