50=((3e-20)+e)/2

Solution for 50=((3e-20)+e)/2 equation:

50=((3e-20)+e)/2

We move all terms to the left:

50-(((3e-20)+e)/2)=0

We multiply all the terms by the denominator


-(((3e-20)+e)+50*2)=0


We calculate terms in parentheses: -(((3e-20)+e)+50*2), so:

((3e-20)+e)+50*2

We add all the numbers together, and all the variables

((3e-20)+e)+100


We calculate terms in parentheses: +((3e-20)+e), so:

(3e-20)+e

We add all the numbers together, and all the variables

e+(3e-20)

We get rid of parentheses

e+3e-20

We add all the numbers together, and all the variables

4e-20

Back to the equation:

+(4e-20)


We get rid of parentheses

4e-20+100

We add all the numbers together, and all the variables

4e+80

Back to the equation:

-(4e+80)


We get rid of parentheses

-4e-80=0

We move all terms containing e to the left, all other terms to the right

-4e=80

e=80/-4

e=-20