50=(1+2x)/(.050-x)(0.20-x)

Solution for 50=(1+2x)/(.050-x)(0.20-x) equation:

50=(1+2x)/(.050-x)(0.20-x)

We move all terms to the left:

50-((1+2x)/(.050-x)(0.20-x))=0


Domain of the equation: (.050-x)(0.20-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.20-x)!=-.050

x∈R


We add all the numbers together, and all the variables

-((2x+1)/(-1x+0.05)(-1x+0.2))+50=0

We multiply parentheses ..

-((2x+1)/(+x^2-0.2x-0.05x+0.01))+50=0

We multiply all the terms by the denominator


-((2x+1)+50*(+x^2-0.2x-0.05x+0.01))=0


We calculate terms in parentheses: -((2x+1)+50*(+x^2-0.2x-0.05x+0.01)), so:

(2x+1)+50*(+x^2-0.2x-0.05x+0.01)

determiningTheFunctionDomain
50*(+x^2-0.2x-0.05x+0.01)+(2x+1)

We multiply parentheses

50x^2+0x+0x+(2x+1)+0.5

We get rid of parentheses

50x^2+0x+0x+2x+1+0.5

We add all the numbers together, and all the variables

50x^2+4x+1.5

Back to the equation:

-(50x^2+4x+1.5)


We get rid of parentheses

-50x^2-4x-1.5=0

a = -50; b = -4; c = -1.5;
Δ = b2-4ac
Δ = -42-4·(-50)·(-1.5)
Δ = -284
Delta is less than zero, so there is no solution for the equation