50=(2x)+(3x-10)

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Solution for 50=(2x)+(3x-10) equation:



50=(2x)+(3x-10)
We move all terms to the left:
50-((2x)+(3x-10))=0
We calculate terms in parentheses: -(2x+(3x-10)), so:
2x+(3x-10)
We get rid of parentheses
2x+3x-10
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
We get rid of parentheses
-5x+10+50=0
We add all the numbers together, and all the variables
-5x+60=0
We move all terms containing x to the left, all other terms to the right
-5x=-60
x=-60/-5
x=+12

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