50=(2x)+(3x-10)

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Solution for 50=(2x)+(3x-10) equation: 



50=(2x)+(3x-10)

We move all terms to the left:

50-((2x)+(3x-10))=0



We calculate terms in parentheses: -(2x+(3x-10)), so:

2x+(3x-10)

We get rid of parentheses

2x+3x-10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

-5x+10+50=0

We add all the numbers together, and all the variables

-5x+60=0

We move all terms containing x to the left, all other terms to the right

-5x=-60

x=-60/-5

x=+12

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