50=(3-c)*10

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Solution for 50=(3-c)*10 equation:



50=(3-c)*10
We move all terms to the left:
50-((3-c)*10)=0
We add all the numbers together, and all the variables
-((-1c+3)*10)+50=0
We calculate terms in parentheses: -((-1c+3)*10), so:
(-1c+3)*10
We multiply parentheses
-10c+30
Back to the equation:
-(-10c+30)
We get rid of parentheses
10c-30+50=0
We add all the numbers together, and all the variables
10c+20=0
We move all terms containing c to the left, all other terms to the right
10c=-20
c=-20/10
c=-2

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