50=(3x-5)x

Solution for 50=(3x-5)x equation:

50=(3x-5)x

We move all terms to the left:

50-((3x-5)x)=0


We calculate terms in parentheses: -((3x-5)x), so:

(3x-5)x

We multiply parentheses

3x^2-5x

Back to the equation:

-(3x^2-5x)


We get rid of parentheses

-3x^2+5x+50=0

a = -3; b = 5; c = +50;
Δ = b2-4ac
Δ = 52-4·(-3)·50
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*-3}=\frac{-30}{-6}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*-3}=\frac{20}{-6}
=-3+1/3
$