50=-10(a-3)-20

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Solution for 50=-10(a-3)-20 equation: 



50=-10(a-3)-20

We move all terms to the left:

50-(-10(a-3)-20)=0



We calculate terms in parentheses: -(-10(a-3)-20), so:

-10(a-3)-20

We multiply parentheses

-10a+30-20

We add all the numbers together, and all the variables

-10a+10

Back to the equation:

-(-10a+10)



We get rid of parentheses

10a-10+50=0

We add all the numbers together, and all the variables

10a+40=0

We move all terms containing a to the left, all other terms to the right

10a=-40

a=-40/10

a=-4

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