50=10(z+52)

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Solution for 50=10(z+52) equation: 



50=10(z+52)

We move all terms to the left:

50-(10(z+52))=0



We calculate terms in parentheses: -(10(z+52)), so:

10(z+52)

We multiply parentheses

10z+520

Back to the equation:

-(10z+520)



We get rid of parentheses

-10z-520+50=0

We add all the numbers together, and all the variables

-10z-470=0

We move all terms containing z to the left, all other terms to the right

-10z=470

z=470/-10

z=-47

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