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50=10+2(p+5)
We move all terms to the left:
50-(10+2(p+5))=0
We calculate terms in parentheses: -(10+2(p+5)), so:We get rid of parentheses
10+2(p+5)
determiningTheFunctionDomain 2(p+5)+10
We multiply parentheses
2p+10+10
We add all the numbers together, and all the variables
2p+20
Back to the equation:
-(2p+20)
-2p-20+50=0
We add all the numbers together, and all the variables
-2p+30=0
We move all terms containing p to the left, all other terms to the right
-2p=-30
p=-30/-2
p=+15
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