50=2(3y-4)=4y+3

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Solution for 50=2(3y-4)=4y+3 equation: 



50=2(3y-4)=4y+3

We move all terms to the left:

50-(2(3y-4))=0



We calculate terms in parentheses: -(2(3y-4)), so:

2(3y-4)

We multiply parentheses

6y-8

Back to the equation:

-(6y-8)



We get rid of parentheses

-6y+8+50=0

We add all the numbers together, and all the variables

-6y+58=0

We move all terms containing y to the left, all other terms to the right

-6y=-58

y=-58/-6

y=9+2/3

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