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50=25+(5x+5)
We move all terms to the left:
50-(25+(5x+5))=0
We calculate terms in parentheses: -(25+(5x+5)), so:We get rid of parentheses
25+(5x+5)
determiningTheFunctionDomain (5x+5)+25
We get rid of parentheses
5x+5+25
We add all the numbers together, and all the variables
5x+30
Back to the equation:
-(5x+30)
-5x-30+50=0
We add all the numbers together, and all the variables
-5x+20=0
We move all terms containing x to the left, all other terms to the right
-5x=-20
x=-20/-5
x=+4
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