50=3(s+-6)-2(s-2)

Solution for 50=3(s+-6)-2(s-2) equation:

50=3(s+-6)-2(s-2)

We move all terms to the left:

50-(3(s+-6)-2(s-2))=0

We add all the numbers together, and all the variables

-(3(s-6)-2(s-2))+50=0


We calculate terms in parentheses: -(3(s-6)-2(s-2)), so:

3(s-6)-2(s-2)

We multiply parentheses

3s-2s-18+4

We add all the numbers together, and all the variables

s-14

Back to the equation:

-(s-14)


We get rid of parentheses

-s+14+50=0

We add all the numbers together, and all the variables

-1s+64=0

We move all terms containing s to the left, all other terms to the right

-s=-64

s=-64/-1

s=+64