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50=3/2t-t
We move all terms to the left:
50-(3/2t-t)=0
Domain of the equation: 2t-t)!=0We add all the numbers together, and all the variables
t∈R
-(-1t+3/2t)+50=0
We get rid of parentheses
1t-3/2t+50=0
We multiply all the terms by the denominator
1t*2t+50*2t-3=0
Wy multiply elements
2t^2+100t-3=0
a = 2; b = 100; c = -3;
Δ = b2-4ac
Δ = 1002-4·2·(-3)
Δ = 10024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10024}=\sqrt{4*2506}=\sqrt{4}*\sqrt{2506}=2\sqrt{2506}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-2\sqrt{2506}}{2*2}=\frac{-100-2\sqrt{2506}}{4} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+2\sqrt{2506}}{2*2}=\frac{-100+2\sqrt{2506}}{4} $
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