50=5(c+4/5)-9+6c

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Solution for 50=5(c+4/5)-9+6c equation: 



50=5(c+4/5)-9+6c

We move all terms to the left:

50-(5(c+4/5)-9+6c)=0



Domain of the equation: 5)-9+6c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-(5(+c+4/5)-9+6c)+50=0

We multiply all the terms by the denominator


-(5(+c+4+50*5)-9+6c)=0



We calculate terms in parentheses: -(5(+c+4+50*5)-9+6c), so:

5(+c+4+50*5)-9+6c

determiningTheFunctionDomain
5(+c+4+50*5)+6c-9

We add all the numbers together, and all the variables

5(c+254)+6c-9

We add all the numbers together, and all the variables

6c+5(c+254)-9

We multiply parentheses

6c+5c+1270-9

We add all the numbers together, and all the variables

11c+1261

Back to the equation:

-(11c+1261)



We get rid of parentheses

-11c-1261=0

We move all terms containing c to the left, all other terms to the right

-11c=1261

c=1261/-11

c=-114+7/11

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