50=5r(2)

Solution for 50=5r(2) equation:

50=5r(2)

We move all terms to the left:

50-(5r(2))=0

determiningTheFunctionDomain
-5r2+50=0

We add all the numbers together, and all the variables

-5r^2+50=0

a = -5; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-5)·50
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{10}}{2*-5}=\frac{0-10\sqrt{10}}{-10}
=-\frac{10\sqrt{10}}{-10}
=-\frac{\sqrt{10}}{-1}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{10}}{2*-5}=\frac{0+10\sqrt{10}}{-10}
=\frac{10\sqrt{10}}{-10}
=\frac{\sqrt{10}}{-1}
$