50=b(b-5)

Solution for 50=b(b-5) equation:

Simplifying
50 = b(b + -5)

Reorder the terms:
50 = b(-5 + b)
50 = (-5 * b + b * b)
50 = (-5b + b2)

Solving
50 = -5b + b2

Solving for variable 'b'.

Reorder the terms:
50 + 5b + -1b2 = -5b + 5b + b2 + -1b2

Combine like terms: -5b + 5b = 0
50 + 5b + -1b2 = 0 + b2 + -1b2
50 + 5b + -1b2 = b2 + -1b2

Combine like terms: b2 + -1b2 = 0
50 + 5b + -1b2 = 0

Factor a trinomial.
(10 + -1b)(5 + b) = 0

Subproblem 1
Set the factor '(10 + -1b)' equal to zero and attempt to solve:

Simplifying
10 + -1b = 0

Solving
10 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1b = 0 + -10
-1b = 0 + -10

Combine like terms: 0 + -10 = -10
-1b = -10

Divide each side by '-1'.
b = 10

Simplifying
b = 10
Subproblem 2
Set the factor '(5 + b)' equal to zero and attempt to solve:

Simplifying
5 + b = 0

Solving
5 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + b = 0 + -5
b = 0 + -5

Combine like terms: 0 + -5 = -5
b = -5

Simplifying
b = -5
Solution
b = {10, -5}