50=b+2+(3b+10)+1.5(b-5)

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Solution for 50=b+2+(3b+10)+1.5(b-5) equation:



50=b+2+(3b+10)+1.5(b-5)
We move all terms to the left:
50-(b+2+(3b+10)+1.5(b-5))=0
We calculate terms in parentheses: -(b+2+(3b+10)+1.5(b-5)), so:
b+2+(3b+10)+1.5(b-5)
determiningTheFunctionDomain b+(3b+10)+1.5(b-5)+2
We multiply parentheses
b+(3b+10)+1.5b-7.5+2
We get rid of parentheses
b+3b+1.5b+10-7.5+2
We add all the numbers together, and all the variables
5.5b+4.5
Back to the equation:
-(5.5b+4.5)
We get rid of parentheses
-5.5b-4.5+50=0
We add all the numbers together, and all the variables
-5.5b+45.5=0
We move all terms containing b to the left, all other terms to the right
-5.5b=-45.5
b=-45.5/-5.5
b=8+1/3.66666666667

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