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50=x(20-2x)
We move all terms to the left:
50-(x(20-2x))=0
We add all the numbers together, and all the variables
-(x(-2x+20))+50=0
We calculate terms in parentheses: -(x(-2x+20)), so:We get rid of parentheses
x(-2x+20)
We multiply parentheses
-2x^2+20x
Back to the equation:
-(-2x^2+20x)
2x^2-20x+50=0
a = 2; b = -20; c = +50;
Δ = b2-4ac
Δ = -202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{4}=5$
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