50=x-x+x*x

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Solution for 50=x-x+x*x equation:



50=x-x+x*x
We move all terms to the left:
50-(x-x+x*x)=0
We add all the numbers together, and all the variables
-(+x*x)+50=0
We get rid of parentheses
-x*x+50=0
Wy multiply elements
-1x^2+50=0
a = -1; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-1)·50
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{2}}{2*-1}=\frac{0-10\sqrt{2}}{-2} =-\frac{10\sqrt{2}}{-2} =-\frac{5\sqrt{2}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{2}}{2*-1}=\frac{0+10\sqrt{2}}{-2} =\frac{10\sqrt{2}}{-2} =\frac{5\sqrt{2}}{-1} $

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