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50m^2-225m+63=0
a = 50; b = -225; c = +63;
Δ = b2-4ac
Δ = -2252-4·50·63
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{38025}=195$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-195}{2*50}=\frac{30}{100} =3/10 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+195}{2*50}=\frac{420}{100} =4+1/5 $
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