50x(2x-10)=1725

Solution for 50x(2x-10)=1725 equation:

50x(2x-10)=1725

We move all terms to the left:

50x(2x-10)-(1725)=0

We multiply parentheses

100x^2-500x-1725=0

a = 100; b = -500; c = -1725;
Δ = b2-4ac
Δ = -5002-4·100·(-1725)
Δ = 940000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{940000}=\sqrt{10000*94}=\sqrt{10000}*\sqrt{94}=100\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-100\sqrt{94}}{2*100}=\frac{500-100\sqrt{94}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+100\sqrt{94}}{2*100}=\frac{500+100\sqrt{94}}{200}
$