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50x(2x-10)=3x
We move all terms to the left:
50x(2x-10)-(3x)=0
We add all the numbers together, and all the variables
-3x+50x(2x-10)=0
We multiply parentheses
100x^2-3x-500x=0
We add all the numbers together, and all the variables
100x^2-503x=0
a = 100; b = -503; c = 0;
Δ = b2-4ac
Δ = -5032-4·100·0
Δ = 253009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{253009}=503$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-503)-503}{2*100}=\frac{0}{200} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-503)+503}{2*100}=\frac{1006}{200} =5+3/100 $
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