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50x(x-1)=143-5x
We move all terms to the left:
50x(x-1)-(143-5x)=0
We add all the numbers together, and all the variables
50x(x-1)-(-5x+143)=0
We multiply parentheses
50x^2-50x-(-5x+143)=0
We get rid of parentheses
50x^2-50x+5x-143=0
We add all the numbers together, and all the variables
50x^2-45x-143=0
a = 50; b = -45; c = -143;
Δ = b2-4ac
Δ = -452-4·50·(-143)
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30625}=175$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-175}{2*50}=\frac{-130}{100} =-1+3/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+175}{2*50}=\frac{220}{100} =2+1/5 $
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