50x+100(20-x)+500=100x+50(20-x)

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Solution for 50x+100(20-x)+500=100x+50(20-x) equation: 



50x+100(20-x)+500=100x+50(20-x)

We move all terms to the left:

50x+100(20-x)+500-(100x+50(20-x))=0

We add all the numbers together, and all the variables

50x+100(-1x+20)-(100x+50(-1x+20))+500=0

We multiply parentheses

50x-100x-(100x+50(-1x+20))+2000+500=0



We calculate terms in parentheses: -(100x+50(-1x+20)), so:

100x+50(-1x+20)

We multiply parentheses

100x-50x+1000

We add all the numbers together, and all the variables

50x+1000

Back to the equation:

-(50x+1000)



We add all the numbers together, and all the variables

-50x-(50x+1000)+2500=0

We get rid of parentheses

-50x-50x-1000+2500=0

We add all the numbers together, and all the variables

-100x+1500=0

We move all terms containing x to the left, all other terms to the right

-100x=-1500

x=-1500/-100

x=+15

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