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50x/60x+1/5=x
We move all terms to the left:
50x/60x+1/5-(x)=0
Domain of the equation: 60x!=0We add all the numbers together, and all the variables
x!=0/60
x!=0
x∈R
-1x+50x/60x+1/5=0
We calculate fractions
-1x+250x/300x+60x/300x=0
We multiply all the terms by the denominator
-1x*300x+250x+60x=0
We add all the numbers together, and all the variables
310x-1x*300x=0
Wy multiply elements
-300x^2+310x=0
a = -300; b = 310; c = 0;
Δ = b2-4ac
Δ = 3102-4·(-300)·0
Δ = 96100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{96100}=310$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(310)-310}{2*-300}=\frac{-620}{-600} =1+1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(310)+310}{2*-300}=\frac{0}{-600} =0 $
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