50x2+147x-588=0

Solution for 50x2+147x-588=0 equation:

50x^2+147x-588=0

a = 50; b = 147; c = -588;
Δ = b2-4ac
Δ = 1472-4·50·(-588)
Δ = 139209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{139209}=\sqrt{49*2841}=\sqrt{49}*\sqrt{2841}=7\sqrt{2841}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(147)-7\sqrt{2841}}{2*50}=\frac{-147-7\sqrt{2841}}{100}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(147)+7\sqrt{2841}}{2*50}=\frac{-147+7\sqrt{2841}}{100}
$