50y-4-80=12+10y-1

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Solution for 50y-4-80=12+10y-1 equation: 



50y-4-80=12+10y-1

We move all terms to the left:

50y-4-80-(12+10y-1)=0

We add all the numbers together, and all the variables

50y-(10y+11)-4-80=0

We add all the numbers together, and all the variables

50y-(10y+11)-84=0

We get rid of parentheses

50y-10y-11-84=0

We add all the numbers together, and all the variables

40y-95=0

We move all terms containing y to the left, all other terms to the right

40y=95

y=95/40

y=2+3/8

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