50z=50-50-80(1-z)

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Solution for 50z=50-50-80(1-z) equation: 



50z=50-50-80(1-z)

We move all terms to the left:

50z-(50-50-80(1-z))=0

We add all the numbers together, and all the variables

50z-(50-50-80(-1z+1))=0



We calculate terms in parentheses: -(50-50-80(-1z+1)), so:

50-50-80(-1z+1)

determiningTheFunctionDomain
-80(-1z+1)+50-50

We add all the numbers together, and all the variables

-80(-1z+1)

We multiply parentheses

80z-80

Back to the equation:

-(80z-80)



We get rid of parentheses

50z-80z+80=0

We add all the numbers together, and all the variables

-30z+80=0

We move all terms containing z to the left, all other terms to the right

-30z=-80

z=-80/-30

z=2+2/3

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