51-(2c+3)=4(c+5)=c

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Solution for 51-(2c+3)=4(c+5)=c equation: 



51-(2c+3)=4(c+5)=c

We move all terms to the left:

51-(2c+3)-(4(c+5))=0

We get rid of parentheses

-2c-(4(c+5))-3+51=0



We calculate terms in parentheses: -(4(c+5)), so:

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We add all the numbers together, and all the variables

-2c-(4c+20)+48=0

We get rid of parentheses

-2c-4c-20+48=0

We add all the numbers together, and all the variables

-6c+28=0

We move all terms containing c to the left, all other terms to the right

-6c=-28

c=-28/-6

c=4+2/3

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